home
Home
home
JAMB
home
WAEC
home
NECO
home
NABTEB
home
NEWS

Good Day,
WAEC Starts on 4th of August and Our payments for the Questions and Answers Supplies Will End Soon
  Pay Now and join the success team.

WAEC GCE 2019 - MATHEMATICS ANSWER
WAEC GCE 2019 - MATHEMATICS ANSWER

WAEC GCE 2019 - MATHS ANSWER


+++++++++++++++++++++++++++
MATHS OBJ
1-10: BBDCCBCBBA
11-20: BCBDCDBDDB
21-30: BCBDDBAACA
31-40: AABBDABCCB
41-50: BBBDBCBCDB

+++++++++++++++++++++++++++

ANSWERS:


(1a) 
Table for multiplication (x) in mod 8
Using (2, 3, 5, 7)

In a tabular form.
Under (x) 2, 3, 5, 7
Under 2 4, 6, 2, 6
Under 3 6, 1, 7, 5
Under 5 2, 7, 1, 3
Under 7 6, 5, 3, 1

(1bi)
3(x)n = 5
3 × n = 5 + cont. Of mod 8 to be divisible by 3;
3n = 5 + 8 + 8
3n = 21
n = 21/3
n = 7

(1bii)
n(x)n = 1
n * n = 1 + 8
n² = 9
n = √9
n = 3



===================

(2a) 
Given; slant height l = 18.7cm
Diameter, d = 24cm
π = 22/7
But, Curved surface area of cone = πrl
=π(d/2)l
= 22/7 × 24/2 × 18.7
=9873.6/14 = 705cm²

(2b) 
128^x × 2/16^(1-x) = 8⅔x
= 2^7x × 2/2^4(1-x) = 2³(⅔x) 
= 2^7x + 1/2^4(1-x) = 2^2x
Cross multiply 
2^4(1 - x) + 2x = 2^7x + 1
4(1 - x) + 2x = 7x + 1
4 - 4x + 2x = 7x + 1
4 - 2x = 7x + 1
9x = 3
X = 3/9 = 1/3



=====================

(3a) 
3√3/2 - 4√2/3 - √24
=3√3/2 - 4√2/√3 -√6*4
=(3√3/√2 × √2/√2) - (4√2/√3 × √3/√3) - 2√6
=3√6/2 - 4√6/3 - 2√6
=(3/2 - 4/3 - 2)√6
=(9 - 8 - 12)√6
= -11/6√6

(3bi) prob(only one passes) = m passes and N fails or M fails and N passes
Prob (M passes) = 2/3; prob(M fails) = 1 - 2/3 = 1/3
Prob(N passes) = 4/5; prob(N fails) = 1 - 4/5 = 1/5
Prob(only one passes) = (2/3 × 1/5) + (1/3 × 4/5)
= 2/15 + 4/15
= 6/15
= 2/15

(3bii) 
prob(at least one passes) = prob(only one passes) + prob(both parties) 
= 2/5 + (2/3 × 4/5)
= 2/5 + 8/15
= 6/15 + 8/15
= 14/15



=====================

(4a)
17²=X²+15²
17²=X²+225
289-225=X²
64=X² 
C=√64=8
Tanθ=18/15
Tanθ/1+2tanθ=18/15/1+2(8/15)=8/15/1+16/15
=8/15÷31/15=8/15*15/31=8/31

(4b) 
Log10 y/log10 64 = 1/2
Cross multiply 
2log y = log10 64
Log10 y² = log10 64
y = √64
y = ±8





===================

(5a)
Obtuse Reflex 
Obtuse Obtuse = 164°

OMP + OPM + Obtuse MOP = 180°(angles in a triangle) 
But OMP = OPM = x(radius of the circle and hence base angles are the same) 

2x + 164 = 180
2x = 180 - 164
2x = 16°
X = 16/2 = 8°

Also MNP = 1/2×obtuseMOP
= 1/2 × 164°
= 82°

Now; MNP + NMP + NPM = 180° (angles in a triangle) 
82 + (52+8) + (m+8) = 180°
m + 150 = 180°
M = 180 - 150
M = 30°

(5b) 
Portion of land for cassava = 2/5
Portion of land for plantain = 1/3 × (1 - 2/5)
= 1/3 × 3/5
= 1/5

Portion of land for yam = 1 -(2/5 + 1/5)
1 - (3/5)
=2/5



========================

(8ai) 
a + 4d = 11 .....i
a + 7d = 20 .... ii

a + 7d = 20
- a + 4d = 11
3d = 9

d = 9/3
d = 3
Using eqn i
a + 4(3) = 11
a + 12 = 11
a = 11 - 12
a = -1

T12 = a + 11d
= -1 + 11(3)
= -1 + 33
= 32

(8aii)
Sn = n/2[20 +(n - 1)d]

S12 = 12/2[2(-1)+(12-1)3]
=6[-2 + (11)3 ]
= 6[-2 + 33]
= 6[31]
= 1806

(8b) 
Let the S.p = M
15% of m = 15m/150
= 3m/20 (Discount) 

Therefore; collected = M -3m/20
So M/1 - 3M/20 =36000/1
20m - 3m = 720000
17m = 720000
m = 720000/17
M = 42352.94%

Discount = 42352.94 × 3/20
Discount = #6,352.94






=====================

(9ai) 
Draw the Venn diagram

(9aii) 
No selected for biology but neither physics nor mathematics = 36

(9aiii) 
No not selected for any of three subjects = 11

(9b) 
Mean = 22+18+(2x+1)+10+20/5 = 15
2x + 71 = 75
2x = 75 - 71
2x = 4
X = 4/2 = 2

The numbers are: 22, 18, 5, 10 and 20
Arranging in ascending order, we have 5, 10, (18), 20, 22

The median is 18



======================

(10a) 
Loan borrowed = 80/100 x 350,000
=280,000
Amount paid to the bank after 8 years = P + I 
= P + PRT/100
=280000 + 280000x7x8/100
=280,000 + 156,800
Amount = #436,800

Total cost of house to the man = #350,000 + Interest
= #350,000 + 156,800
= #506,800

(10b) 
Percentage increase in cost of house = 506,800 - 350,000 x 100%
= 156,800/350,000 x 100%
= 44.8%

(10c) 
Percentage loss = loss/cost price x 100%
=(506,800 + 10,000) - 460,000/(506,800 + 10,000) x 100%
= 516,800 - 460,000/516,800 x 100%
56,800/516,800 x 100%
= 0.1099 x 100%
= 10.99%



=====================

(12)


=====================

(13a)
Draw the diagram 

(i) Extend DO to touch AB at M
AOD + AOM = 180°(angles on a straight line) 
130 + AOM = 180°
AOM = 180 - 130 = 50°

Also; 
BMO = BAO + AOM(Ext angle = sum of two opposite interior angles of a triangle) 
BMO = 26 + 50 = 76°
Also; ABD = 1/2AOD(angle at centre = twice angle at circum) 
ABD = 1/2 × 130
=65°
Hence ODB + ABD + BMO = 180°(sum of angles in a triangle) 
ODB + 65° + 76° = 180°
ODB = 180 - 141
= 39°

(ii) BOD + ODB + DBO = 180°(sum of angles in a triangle) 
But ODB = DBO(base angles of an isosceles triangle) 
BOD + 39° + 39° = 180°
BOD + 78° = 180°
BOD = 180 - 78 = 102°

(13b)

|1 2 6
3|1,3 2,3 (6,3)
4|1,4 2,4 (6,4)
5|1,5 2,5 (6,5)

prob (greater than 7) = 3/9 = 1/3







+++++++++++++++++++++++++++
ANSWER LOADING......
+++++++++++++++++++++++++++






0 Response
FORUM POST LOCKED FOR COMMENTING

Ads; Click Here Now to See How to Make Cool Cash Here in Examface.net

Contact Mr.prof
| wakagist|